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Bulletin of the Australian Mathematical Society· 2026Q2

ON SPARSE HOLES AND A FINITE-FOLD PROBLEM OF NATHANSON CONCERNING MINIMAL ADDITIVE COMPLEMENTS

Đặng Võ Phúc

Short summary

This paper proves a finite-fold version of a sparse-hole obstruction for minimal additive complements, showing that if the complement of a set W (with inf W = 1) has a specific structure related to 'h' copies of itself, then no minimal additive complement exists.

AI-generated from the title and abstract; the full text is not read.

Key points

  • The study investigates minimal additive complements for sets of integers W, where inf W = 1.
  • It extends previous results on sparse-hole conditions that prevent the existence of minimal additive complements.
  • The paper proves a finite-fold version of the sparse-hole obstruction.
  • The core finding is that a specific structure of the complement W̄, related to 'h' copies of itself, implies the nonexistence of a minimal additive complement.

AI-generated from the title and abstract; the full text is not read.

Abstract

Abstract Let W ⊆ Z $W\subseteq \mathbb Z$ upper W subset of or equal to double struck upper Z be bounded below and normalised by inf W = 1 $\inf W=1$ inf upper W equals 1 , and put W ― = Z > 0 ∖ W $\overline W=\mathbb Z_{>0}\setminus W$ upper W overbar equals double struck upper Z Subscript greater than 0 Baseline minus upper W . Nathanson asked whether infinite sets of integers admit minimal additive complements. Chen and Yang [‘On a problem of Nathanson related to minimal additive complements’, SIAM J. Discrete Math. 26 (2012), 1532–1536] proved that the two-sided case is positive and that sufficiently large consecutive gaps in W ― $\overline W$ upper W overbar force nonexistence in the one-sided case. Chen and Ding [‘On a problem of Nathanson on nonminimal additive complements’, Bull. Aust. Math. Soc. 114 , 6–13] isolated a sparse-hole condition under which no ordinary minimal complement exists. We prove a finite-fold version of this sparse-hole obstruction. For an integer h ≥ 1 $h\geq 1$ h greater than or equals 1 , write h C = C + ⋯ + C $hC=C+\cdots +C$ h upper C equals upper C plus midline horizontal ellipsis plus upper C . We show that if W ― $\overline W$ upper W overbar<

The authors' abstract, as published at the source. Bulletin of the Australian Mathematical Society, 2026 · DOI ↗

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Field: Discrete Mathematics and Combinatorics

Discrete Mathematics and CombinatoricsMathematics